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Before we formulate the theorem of FUBINI we consider, as motivation, two examples for its application:
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Assumptions for the theorem of FUBINI [sect:4-1] Let (S1, B1, μ1) and (S2, B2, μ2) be measure spaces, which are generated by rings B10⊂B1 and B20⊂B2 . Definie a measure space (S,B,μ) with S := S1×S2 , where B and μ are generated by the elementary product measure μ1×μ2 (see sect:1-2-(iv) and satz:2-9). We then also write μ=μ1×μ2 .
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Theorem of FUBINI [satz:fubini] Let μ=μ1×μ2 with the assumptions in sect:4-1 and f∈L(μ;Y) . Then
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Now we present sone examples, which show how th theorem of FUBINI can be used to compute special integrals.
One of the most important constructions using the LEBESGUE integral in Rn is the convolution of two integrable functions. For the proof, that this convolution is well defined, the theorem of FUBINI is used. The convolution is often used, to approximate functions by "smooth functions" (usually infinite differentiable functions) with respect to the integral norm.
The second part of this chapter deals with the transformation formula satz:4-12. For the proof we need two preparating lemmata. In lemma:4-10 we see, that images of LEBESGUE-null sets under local LIPSCHITZ continuous transformations are again LEBESGUE null sets. The second lemma lemma:4-11 confirms the intuitive idea of the influence affine linear mappings to the LEBESGUE measure of measurable sets.
The second lemma is the transformation rule for linear transformations, where we restrict ourselves as a preliminary step to the transformation of a special class of sets.
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Lemma [lemma:4-11] Let τ:Rn → Rn be an affine mapping with
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After these preparations we are ready to prove the following transformation theorem for the LEBESGUE integral on Rn .
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Transformation theorem [satz:4-12] Let U, V⊂Rn be open sets and τ:U → V a C1 -diffeomorphism. Then
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